What happens when you attempt to compile and run the following code?
#include
using namespace std;
int main()
{
int i=2;
switch(i)
{
case 1:
cout<<"Hello";
case 2:
cout<<"world";
case 3:
cout<<"End";
} return 0;
}
What happens when you attempt to compile and run the following code?
#include
#include
using namespace std;
const int size = 3;
class A {
public:
string name;
A() { name = "Bob";}
A(string s) { name = s;}
A(A &a) { name = a.name;}
};
class B : public A {
public:
int *tab;
B() { tab = new int[size]; for (int i=0; i B(string s) : A(s) { tab = new int[size]; for (int i=0; i ~B() { delete tab; } void Print() { for (int i=0; i cout << name; } }; int main () { B b1("Alan"); B b2; b1.tab[0]=0; b1.Print(); b2.Print(); return 0; }
What happens when you attempt to compile and run the following code?
#include
using namespace std;
int main() {
float i = 1.0 / 2 * 2 / 1 * 2 / 4 * 4 / 2;
cout << i;
return 0;
}
What happens when you attempt to compile and run the following code?
#include
#include
using namespace std;
void fun(int i);
int main()
{
int i=0;
i++;
for (i=0; i<=5; i++)
{
fun(i);
}
return 0;
}
void fun(int i)
{
if (i==3)
return;
cout << i;
}
What is the output of the program if characters 'h', 'e', 'l', 'l' , 'o' and enter are supplied as input?
#include
#include
using namespace std;
void f();
int main()
{
f();
return 0;
}
void f()
{
char c;
c = cin.get();
cout << c;
if(c != '\n')
f();
}